Question

A car moving at a speed of 10 m/s. It undergo two consecutive turns left and right respectively. What is the magnitude of change in velocity..?​

Answer 1

Answer:

Change in velocity of a particle in circle in given by,

∣Δ

v

ˉ

∣=

v

1

2

+v

2

2

+2v

1

v

2

cos(π−θ)

Since [∣

v

1

ˉ

∣=∣

v

2

ˉ

∣]=v

∣Δ

v

ˉ

∣=2vsin

2

θ

On putting the values of vandθ

=(2×10)×sin(30

o

)

=10m/s

Hence the change in velocity is 10m/s