a car moving at a speed of 54 km/hr starts retarding at 3m/s after what time will the car stop
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Answer:
5 seconds
Explanation:
u=54=54×5/18=15m/s
v=0m/s
a=(-3)m/s^(-2)
v=u+a×t
t=v-u/a
t=0-15/-3
t=-15/-3
t=5seconds
hope this will help you
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