Question

a car moving at a speed of 54 km/hr starts retarding at 3m/s after what time will the car stop​

Answer 1

Answer:

5 seconds

Explanation:

u=54=54×5/18=15m/s

v=0m/s

a=(-3)m/s^(-2)

v=u+a×t

t=v-u/a

t=0-15/-3

t=-15/-3

t=5seconds

hope this will help you