A car moving on a road with uniform acceleration cover 20 meters in the first second and 30 meters in the next second. What is its acceleration
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Step-by-step explanation:
Let u0 is initial speed. to get distance covered in first one second with acceleration a, we need to use equation "S=ut+(1/2)at2 "
hence for first one second we have : u0+(1/2)a = 20 ....................(1)
at the end of first one second, speed u1 is : u1 = u0+a
Hence for next one second we have = (u0+a)+(1/2)a = 30 ..............(2)
By solving (1) and (2), we get u0 = 15 m/s, a = 10 m/s2
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