A car moving on a straight road at 5 m/s. It is accelerated at 3 m/s^2. What will be its velocity after 4 seconds ?
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Answered by
0
Explanation:
v=u+at
v=5+(3×4)
v=17m/s
Answered by
31
Given :-
- Initial velocity = 5 m/s
- Acceleration = 3 m/s²
- Time = 4 sec
To Find :-
- Final Velocity
Solution :-
- u = 5 m/s
- a = 3 m/s²
- t = 4 sec
Substituting the value in 1st equation of motion :-
➩ v = u + at
➩ v = 5 + 3 × 4
➩ v = 5 + 12
➩ v = 17 m/s
Final velocity = 17 m/s
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