Question

A car moving speed 40km/hr can be stopped by applying breaks at least 2 mr if the car is moving with a speed 80 km/hr minimum stopping distance

Answer 1

Answer:

4 mr.

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Answer 2

Step-by-step explanation:

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Initial velocity, u = 40 km/h = 40 × (5/18) = 200/18 m/s

Final velocity, v = 0

Distance travelled before coming to rest, s = 2 m

Using, v2 = u2 + 2as

=> a = -u2/(2s)

=> a = -30.864 m/s²

♦ Again,

u = 80 km/h = 400/18 m/s

v = 0

a = -30.864m/s²

Now, v2 = u2 + 2as

=> s = -u2/(2a) = 8m

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