Question

A car moving towards north at a speed of 10 m/s turns right within 10 s maintaining the same speed.
Average acceleration of the car during this time interval is​___.Answer with full explanation.

Answer 1

Answer:

|a| = √2 m/s^2 towards S-E

Explanation:

Vf = 10 i

Vi = 10 j

∆V = Vf - Vi = 10 i - 10 j

a = ∆V / ∆t = i - j

|a| = √2 m/s^2 towards S-E