Question

a car moving towards north at speed of 10m/s turns right within 10s maintaing the same speed average acceleration of the car during this time interval is

Answer 1

Answer:

√2 m/s² South East

Explanation:

a car moving towards north at speed of 10m/s turns right within 10s maintaing the same speed average acceleration of the car during this time interval is

Initial Velocity = 10 m/s towards north

= 0i + 10j

turns right => towards East

Final Velocity = 10i + 0j

Change in Velocity = Final Velocity - Initial Velocity

=  10i + 0j - (0i + 10j)

= 10i - 10j

time = 10 sec

Acceleration = (10i - 10j) /10 = i - j

Magnitude of acceleration = √1² + (-1)² = √2 m/s²

Angle = tan⁻¹(-1/1) = -45°

-45° means South East