a car moving towards north at speed of 10m/s turns right within 10s maintaing the same speed average acceleration of the car during this time interval is
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Answer:
√2 m/s² South East
Explanation:
a car moving towards north at speed of 10m/s turns right within 10s maintaing the same speed average acceleration of the car during this time interval is
Initial Velocity = 10 m/s towards north
= 0i + 10j
turns right => towards East
Final Velocity = 10i + 0j
Change in Velocity = Final Velocity - Initial Velocity
= 10i + 0j - (0i + 10j)
= 10i - 10j
time = 10 sec
Acceleration = (10i - 10j) /10 = i - j
Magnitude of acceleration = √1² + (-1)² = √2 m/s²
Angle = tan⁻¹(-1/1) = -45°
-45° means South East
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