A car moving with a speed of 18 km/hr stops in 5s after applying the brakes what is the speed of the car after 2s of applying brakes
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Answered by
2
heya you answer _______
u=18km/h=18×5/18=5m/s
t=5s
v=0
first we find acceleration
a=(v-u)/t
a=(0-5)/5= -1 m/s^2
now speed of car after 2 sec i.e v
for that t=2 sec
v=u+at
v=5+(-1*2)
v=5-2=
v=3 m/s
so speed after 2 sec is 3m/s
u=18km/h=18×5/18=5m/s
t=5s
v=0
first we find acceleration
a=(v-u)/t
a=(0-5)/5= -1 m/s^2
now speed of car after 2 sec i.e v
for that t=2 sec
v=u+at
v=5+(-1*2)
v=5-2=
v=3 m/s
so speed after 2 sec is 3m/s
Answered by
0
speed=18km\hr
change it to m\s
speed=18*5\18
speed=5m\s
so u=5m\s
v=0m\s
t= 5s
d= v-u\t
d=0-5\5
d= -1
now you can do for 2 sec
change it to m\s
speed=18*5\18
speed=5m\s
so u=5m\s
v=0m\s
t= 5s
d= v-u\t
d=0-5\5
d= -1
now you can do for 2 sec
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