A car moving with a speed of 20 m/s can be stopped by applying brakes, after traveling a distance of 2m. the retardation of the car is ?
a) 50 m/s^2
b) 100 m/s^2
c) 150 m/s^2
d) 200 m/s^2
please answer it ASAP
Answers
Answered by
2
U=20m/s
V=0
S=2m
retardation =(negative acceleration )
v2-u2=2as
o -400=2×a×2
-400=4×a
a=-400/4
-a=100mps^2
:::retardation =100m/s^2
V=0
S=2m
retardation =(negative acceleration )
v2-u2=2as
o -400=2×a×2
-400=4×a
a=-400/4
-a=100mps^2
:::retardation =100m/s^2
Answered by
1
Hi friend,
We know that ,
V²-u² = 2as.
As it has final velocity zero because brakes are applied.
:- v² = u²+2as.
0= (20)² +2×a×2
4a=-400
a=-100m/s².
As the retardation means negative acceleration the negative sign is omitted.
:- the correct answer is option (b).
Hope this helped you a little!!!
We know that ,
V²-u² = 2as.
As it has final velocity zero because brakes are applied.
:- v² = u²+2as.
0= (20)² +2×a×2
4a=-400
a=-100m/s².
As the retardation means negative acceleration the negative sign is omitted.
:- the correct answer is option (b).
Hope this helped you a little!!!
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