A car moving with a speed of 30m/s on a circular track of radius 500m.Its speed is increasing at the rate of 2m/s2.Determine the value of its acceleration.
Answers
Answer:
Explanation:
=> It is given that,
Speed of a car = 30m/s
Radius of circular track = 500m.
Its speed is increasing at the rate of 2m/s2.
Acceleration = ?
=> Total acceleration is equal to the root of the squared sum of centripetal acceleration and tangential acceleration.
Thus, centripetal acceleration, a_n = v²/ radius = 30²/500
Tangential acceleration, a_t = 2 m/s²
=> Total acceleration:
a_total = √ a_t² + a_n²
= √2² + (30²/500)²
= √2² + 1.8²
= √4 + 3.24
= √7.24
= 2.7 m/s²
Thus, the value of the acceleration of a car is 2.7 m/s².
Explanation:
centripetal acceleration, a_n = v²/ radius = 30²/500
Tangential acceleration, a_t = 2 m/s²
=> Total acceleration:
a_total = √ a_t² + a_n²
= √2² + (30²/500)²
= √2² + 1.8²
= √4 + 3.24
= √7.24
= 2.7 m/s²
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