A car moving with a speed of 40kmph can be stopped by applying brakes at least 2 m if the same car is moving with the speed of 80kmph what is the minimum stopping distance
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If F is retarding force and s the stopping distance then
1/2 m2 =Fs
For same retarding force, s a v2
s_2/s_1 = (v_2/v_1 )^2 =((80 km/h)/(40 km/h))^2 =4
s2 = 4s1 = 4 × 2 = 8m
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Answer:
Explanation:
If F is retarding force and s the stopping distance then
1/2 m2 =Fs
For same retarding force, s a v2
s_2/s_1 = (v_2/v_1 )^2 =((80 km/h)/(40 km/h))^2 =4
s2 = 4s1 = 4 × 2 = 8m
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