Question

A car of mass 1200 kg is moving with a constant velocity of 60 kmph. When the brakes causing 4.5 kn force are applied the distance travelled before the car comes to rest will be

Answer 1

m=1200

u=60km/h

v=0

f=4.5n

f=ma

4.5=1200×a

45/10*1200=a

45\1200=a

a=0.00375

v²=u²+2as

ab put karke s find kar lo

Answer 2

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F=ma

Let’s collect the givens (and identify the unknown as “F” for force):

Distance is 50 m

Mass (m) is 1,000 Kg (i.e., a metric ton)

Initial velocity vi is 20 m/s

Final velocity vi is zero

The deceleration is a velocity change of -20 m/s (which over a distance of 50 m), but we don’t know the time (t) over which it occurs.

Assuming the acceleration (or negative deceleration) was constant, the average velocity was 10 m/s, so the time to travel 50m was 5 seconds Therefore the acceleration was:

−20ms÷5s

−4ms2

Therefore, given F=ma or

F=1000Kg∗(−4)m/s/s,

the retarding force is -4000 N (since 1 N is defined as 1 Kg m /s^2)