A car moving with a speed of 50 m/sec can be stopped by brakes after at least 6 cm. If the mass of car is 200 kg how much force is applied by the driver and also find time.
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Given, u=50km/hr=50×185=18250m/s
v=0s=6m(at least)
By third equation by motion,
v2=u2+2as0=(18250×18250)+2(−a)(s)0=192.90−12aa=12192.90=16.07
Now applying third equation of motion,
v2=u2+2as⟹0=(100×185)2+2(−16.07)(s)⟹0=771.60−32.14s⟹s=32.14771.60=24.00
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