Question

A car moving with a speed of 54km/h is brought to rest within 10sec by applying break find the retardation due to breaks?

Answer 1

v=0m/s (it comes to rest)
u=54km/hr =15m/sec
t=10 sec
Retardation = v-u/t
0-15/10
- 15/10
- 1.5

Answer 2

Answer:

Explanation:

final velocity=0

intial velocity=54kmph

time=10 seconds

units need to be same

so,

54*5/18=15

acceleration=change in velocity/time taken

acceleration =v-u/t

0-15/10

= -3/2