A car moving with a speed of 54km/h is brought to rest within 10sec by applying break find the retardation due to breaks?
Answers
Answered by
52
v=0m/s (it comes to rest)
u=54km/hr =15m/sec
t=10 sec
Retardation = v-u/t
0-15/10
- 15/10
- 1.5
u=54km/hr =15m/sec
t=10 sec
Retardation = v-u/t
0-15/10
- 15/10
- 1.5
Answered by
17
Answer:
Explanation:
final velocity=0
intial velocity=54kmph
time=10 seconds
units need to be same
so,
54*5/18=15
acceleration=change in velocity/time taken
acceleration =v-u/t
0-15/10
= -3/2
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