a car moving with a speed of 54km/hr on applying brakes stopped in 8sec.calculate the acceleration?
Answers
Answered by
5
we have
v = u + at
the acceleration will be given as
a = (v - u) / t
here as the car comes to rest
v = 0
and given
u = 54 km/hr = 15 m/s
t = 8
so,
a = (0 - 15) / 8
thus,
a = -1.875 m/s2
plz react thanks
v = u + at
the acceleration will be given as
a = (v - u) / t
here as the car comes to rest
v = 0
and given
u = 54 km/hr = 15 m/s
t = 8
so,
a = (0 - 15) / 8
thus,
a = -1.875 m/s2
plz react thanks
sujan3:
how did 54km/hr converted into 15m/sec
by using the formula to convert km /hr to m/sec...which is divided km/hr by 1000/3600
if you want to convert m/sec to km/hr ..divide it by 3600 /1000
Answered by
2
u =initial velocity
v =final velocity
a =acceleration
t =time
According to question
u=54km/hr
we will convert it into m/sec
54 ×1000 /3600
15 m
u =15m
v =0m/sec
t =8 sec
a =v -u /t
a=0-15 /8
a =-15 /8 m/sec^2
a .=-1.875 m /sec ^2
v =final velocity
a =acceleration
t =time
According to question
u=54km/hr
we will convert it into m/sec
54 ×1000 /3600
15 m
u =15m
v =0m/sec
t =8 sec
a =v -u /t
a=0-15 /8
a =-15 /8 m/sec^2
a .=-1.875 m /sec ^2
hope it helps you
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