Question

a car moving with a velocity of 10 metre per second accelerate and attains a velocity of 20 metre per second in 5 second calculate the force extended on the car if the mass of the car is 900 kg​

Answer 1

Answer:

1800N

Explanation:

Given:

• Mass of the car = m = 900 kg
• Initial velocity of the car = u = 10 m/s
• Final velocity of the car = v = 20 m/s
• Time tak = t = 5 seconds

To find:

• Force extended o the car

Force = m(v-u)/t

force = 900(20-10)/5

Force = 900(10)/5

Force = 9000/5

Force = 1800

The force exerted on the car is equal to 1800 Newtons

Answer 2

✰ Given -

• Mass (m) = 900kg
• Initial Velocity (u) = 10m/s
• Final Velocity (v) = 20m/s
• Time (t) = 5 sec

✰ To Find -

• Force = ?

✰ Solution -

We know Formula of Force,

$✓ \: f = ma$

But, According to given Conditions Formula will be,

$✓ \: f = m \times \frac{(v - u)}{t}$

Placing Values,

$⟶f = 900 \times \frac{(20 - 10)}{5}$

$⟶f = 900 \times \frac{\cancel{10}}{\cancel{5}}$

$⟶f = 900 \times 2$

$⟶f = 1800N$

⛬ Force exerted on car is 1800N