Question

a car moving with a velocity of 30 metre per second is brought to rest in hundred metre with constant retardation the magnitude of retardation will be​

Answer 1

Answer:

9/2 m/s² or 4.5 m/s²

Explanation:

Given

u (initial velocity) = 30 m/s

s (displacement) = 100 m

v (final velocity) = 0 m/s (since the body comes at rest)

Apply the third equation of motion 2as = v² - u²

⇒ 2a(100) = 0 - 30²

⇒ 200a = - 900

⇒a = -9/2 m/s²

⇒ a = -4.5 m/s²

[Negative sign shows retardation]

Hence, the magnitude of retardation is 9/2 m/s² or 4.5 m/s²

Answer 2

Answer:

u=30m/s

v=0m/s

s=100m

a=?

v^2=u^2+2as

(0)^2=30^2+2.a.100

0=900+200a

-200a=900

a=4.5m/s^2

thanks for patience