Physics, asked by vg424569, 9 months ago

A car moving with a velocity of lo ms-1 gain a velocity of 30ms after a distance of 4Km the acceleration is​

Answers

Answered by dna63
1

\textbf{\large{\underline{\underline{EXPLANATION:}}}}

\sf{Given}\begin{cases}\sf{u=10ms^{-1}}\\ \sf{v=30ms^{-1}}\\ \sf{s=4km=4000m}\\ \sf{a=??}\end{cases}

\textbf{\underline{Using equation of motion,,}}</p><p>

\mathtt{\boxed{\blue{v^{2}-u^{2}=2as}}}

\textbf{\underline{Putting the given values,,}}</p><p>

\sf{(30)^{2}-(10)^{2}=2a\times{1000}}

\sf{\implies{900-100=2000a}}

\sf{\implies{\cancel\dfrac{800}{2000}=a}}

\sf{\implies{a=0.4 ms^{-2}}}

Therefore,,

\mathtt{\underline{\boxed{\red{a=0.4ms^{-2}}}}}

\rule{200}2

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