Question

A car moving with an initial velocity of 20m/s has an acceleration of 2 ms^−2 What distance will it cover if it comes to rest in 10 s ?



Plz answer fast

Answer 1

Answer:

Correct option is

B

10ms

−1

Retardation =2ms

−2

Time =5s

So, decrease in velocity = retardation × time =(2×5)ms

−1

=10ms

−1

Initial velocity =20ms

−1

So, final velocity = (initial velocity) − (decrease in velocity) =(20−10)ms

−1

=10ms

−1

please mark me as Brainlist