Physics, asked by sushantpatilp30j, 1 year ago

A car moving with certain velocity comes to halt after covering a distance of 62.5m if reatardation was 5m/s2 find the initial velocity of the car

Answers

Answered by sanjay338
22
hi.........................
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Answered by probrainsme101
0

Concept:

Equations of motion:

1) v = u + at

2) s = ut + 1/2 at²

3) v² - u² = 2as

where v = Final velocity of the object

u = Initial velocity of the object

a = Acceleration of the object

t = Time taken

s = Distance covered

Given:

Distance covered by the car, s = 62.5 m

Acceleration, a = -5 m/s²   [-ve sign signifies the retardation (decrease in velocity)

Final velocity, v = 0 m/s  [As car comes to halt means it stops.]

Find:

Initial velocity of the car.

Answer:

Initial velocity of the car is 25 m/s.

Solution:

As we are given only distance, final velocity and acceleration, we will use the third equation of motion for finding the initial velocity of the car.

Let the initial velocity of the car be u.

According to the third equation of motion, we have,

v² - u² = 2as         --------------------------- (i)

s = 62.5 m

a = -5 m/s²

v = 0 m/s

Putting the values in (i), we get

(0)² - u² = 2(-5)(62.5)

-u² = -625

u² = 625

u = √625

u = 25 m/s

Hence, the initial velocity of the car is u = 25 m/s.

#SPJ2

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