a car moving with constant acceleration covers the distance between two points 180 m apart in 6 Dec. it's speed as it passes the second point is 45 m/s . what is its acceleration and it's speed at the first poaint
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V=45 m/s
u=?
a=?
S=180m
T=6 s
We know that
V=u + at
45=u+6a. . Equation 1
By second equation of motion
S=ut +1/2at^2
180=6u +18a equation 2
Solving one and 2 we get
U=15
A=5
________________________
HOPE , IT HELPS ... ✌️
______________________
______________________
V=45 m/s
u=?
a=?
S=180m
T=6 s
We know that
V=u + at
45=u+6a. . Equation 1
By second equation of motion
S=ut +1/2at^2
180=6u +18a equation 2
Solving one and 2 we get
U=15
A=5
________________________
HOPE , IT HELPS ... ✌️
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