Question

A car moving with initial velocity of um/s. ofter applying the breaks,it retardation is 0.5m/s and it stop after 20sec . find the initial velocity and distance traveled by the car . ofter applying breaks​​

Answer 1

Answer:

answer is here

Explanation:

Final velocity   v=0

Using    v=u+at

So,    0=u+(−0.5)×12

⟹ u=6 m/s

Using,   v2−u2=2aS

Or,     0−62=2×(−0.5)×S

⟹ S=36 m

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Answer 2

Answer:

Final velocity v=0

Using v=u+at

So,0=u+(−0.5)×12

⟹ u=6 m/s

Using,   v2−u2=2aS

Or, 0−62=2×(−0.5)×S

⟹ S=36 m

Explanation:

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