Question

A car moving with speed of 50 km/hr can be stopped by brakes after atleast 6 m what will be the minimum stopping distance if the same car is moving at a speed of 100 km/hr

Answer 1

Initial velocity, u = 50 km/h = 50 × (5/18) = 250/18 m/s

Final velocity, v = 0

Distance travelled before coming to rest, s = 6 m

Using, v2 = u2 + 2as

=> a = -u2/(2s)

=> a = -16.075 m/s2

Again,

u = 100 km/h = 500/18 m/s

v = 0

a = -16.075 m/s2

Now, v2 = u2 + 2as

=> s = -u2/(2a) = 24 m

Answer 2

Answer:

24 m

Explanation:

Initial velocity, u = 50 km/h = 50 × (5/18) = 250/18 m/s

Final velocity, v = 0

Distance travelled before coming to rest, s = 6 m

Using, v2 = u2 + 2as

=> a = -u2/(2s)

=> a = -16.075 m/s2

Again,

u = 100 km/h = 500/18 m/s

v = 0

a = -16.075 m/s2

Now, v2 = u2 + 2as

=> s = -u2/(2a) = 24 m

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