Question

A car moving with speed of 72 km / hr is brought in rest in 10sec find the retardation of the car

Answer 1

Hii..
Here is your answer..

Solution:-
Initial velocity(u)=72km/h
To convert it in m/s we'll multiple it by 5/18
$= > 72 \times \frac{5}{18} \\ = > 20$
Initial velocity(u)=20m/s
Final velocity(v)=0m/s
Time =10sec
Now,
$acceleration = \frac{v - u}{t} \\ = > \frac{0 - 20}{10} \\ = > \frac{ - 20}{10} \\ = > - 2$
So,
Retardation= 2m/s^2

Hope it helps uh...✌️✌️✌️

Answer 2

the retardation of the car is -8640000 m/min