Question

a car moving with velocity of 10ms-1 and with a uniform acceleration gains a velocity of 30ms-1 after travelling a distance of 4 km . the time taken is

Answer 1

U = 10m/s

V = 40m/s

S = 4000m

V^2 - U^2 = 2AS

1600 - 100 = 2*A*4000

1500=8000A

A=3/16m/s^2

T=V-U/A

=40-10/(3/16)

=30*16/3

=160seconds

Answer 2

The time taken by the car is 200 seconds.

Explanation:

Given that,

Initial velocity of the car, u = 10 m/s

Final velocity of the car, v = 30 m/s

Distance covered, d = 4 km = 4000 m

To find,

Time taken by the car.

Solution,

Let a is the acceleration of the car. It can be calculated using third equation of motion as :

$a=\dfrac{v^2-u^2}{2d}$

$a=\dfrac{(30)^2-(10)^2}{2\times 4000}$

$a=0.1\ m/s^2$

Let t is the time taken. It is given by using first equation of motion as :

$t=\dfrac{v-u}{a}$

$t=\dfrac{30-10}{0.1}$

t = 200 seconds

So, the time taken by the car is 200 seconds.

Learn more,

Equation of kinematics

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