A car of 700kg moving with 90km/h is brought to rest . Calculate work done by the brake
Answers
Answered by
0
Answer:
The work done to stop the car is 2,18,750 J.
Explanation:
The work done to stop the car will be equal to the kinetic energy of the car. A force should be applied in a direction opposite to the motion of the car. The kinetic energy of the car can be found using the following equation:
K.E = 1/2 (mv²)
Where 'm' is the mass and 'v' is the velocity of the body.
We have, the mass of the car, m = 700 Kg
The velocity of the car, v = 90 Km/h = 25 m/s
∴ The kinetic energy of the car, K.E = 1/2 (700 × 25²)
= 1/2 (700 × 625)
= 2,18,750 J
∴ The work done to stop the car is 2,18,750 J.
Similar questions