A car of mass 1,000 kg is moving at a speed of
20 ms-1
It is brought to rest at a distance of 50 m.
Calculate the net force acting on the car.
4,000 N
3,000 N
2,000 N
1,000 N
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Explanation:
mass = 1000 kg
u = 20 m/s
v = 0 m/s
s = 50 m
using third equation of motion
v² = u²+2as
0² = 20²+2×a×50
-400 = 100a
a = -4 m/s²
F = ma
= -4 × 1000
= -4000
hence force acting = 4,000 N ( in opposite directions)
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