Question

a car of mass 1000 kg moving with a velocity of 40 km /h collides with a tree and comes to stop in 5 seconds . what will be the force exerted by car on the tree

Answer 1

☜☆☞hey friend ☜☆☞

given

m= 1000kg ,

v = 40km/h = 100/9 m/s

Initial momentum of the car = P(initial) = mv = 1000×100/9 = 100000/9kg-m/s

final momentum of the car = P(final) = 0 kg-m/s

Now

Force = [P(f)-P(i)]/t = 100000/-9 = -2222.22 N


¯\_(ツ)_/¯

hope it will help you

Devil_king ▄︻̷̿┻̿═━一

Answer 2

Force=Mass×Accerlation

Mass of Car=1000 kg

Intial Velocity (u) before Striking=40 km/h

In m/s=11.11 m/s

Intial Velocity (u)=11.11 m/s

Final Velocity (v)=0 m/s

Time(t)=5 Seconds.

Find Accerlation.

Use Equation of Motion

V=U+AT

0=11.11+5×A

0-11.11=5A

-11.11/5=A

A=-2.222 m/s

Accerlation=-2.222 m/s

Mass=1000 kg

Force=-2.222×1000

Force exerted by car=-2222 N

$\boxed{\mathbf{Force=-2222\:N}}$