Question

a car of mass 1000 kg when in first gear has a velocity of 18 km / h. it takes 10 secs to accelerate into fifth gear to a velocity of 108 km/ h. compute
(a) change in velocity from first to fifth
(b) acceleration of car assuming acceleration to be uniform.
(c) the force generated by engine
(d) the distance covered by car if the engine is turned off and the road retards its motion at the rate of 2 m/s in every second of motion till car comes to rest.


plss answer in detail

Answer 1

M=1000kg
u=18km/h =5m/s
v=108km/h =30m/s
t=10s
A) change in velocity = v-u
. . . . . . . =30-5=25m/s
B) acceleration =a
. . a=(v-u) /t
a=(30-5)/10
a=25/10
a=2.5m/s²
C) F=ma
. . F=1000×2.5
. . . F=2500 N or 2500 kg m/s²
D) distance=s, u=5 m/s
s=ut + 1/2 a t²
s=5m/s×10s +1/2×-(20m/s² ×100s)
s=50m/s² + 1/2 × - 2000m/s²
s=50m/s² - 1000m/s²
s=1050m
s=1.05 km




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