Question

A car of mass 1000kg first travels forward at 25m/s^2 and then backwards at 15m/s^2. what is the change in the k.E of the car?

Answer 1

M=1000kg

V1=25m/s

V2=15m/s

Change in K.E= M(V2²-V1²)

=1000(225-625)

=1000(-400)

= - 400000joule