A car of mass 1200 kg is moving with a constant speed of 36km/h. The net force acting on the car is
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Answer:
The force applied by the breaks is 3000 N.
Explanation:
Here, m=1200 kg u=36*(1000/3600)m/s = 10 m/s
v=0 m/s and s=20 m
v^2-u^2=2as
0-(10)^2=2a(20)
-100=2a(20)
-5=2a
therefore, a=-2.5 m/s^2
We know that F=ma
Therefore, F=1200*(-2.5)
F= -3000 N
The force applied by the breaks is 3000 N.
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