Question

The radius of a sphere is doubled. Find the increase in percent in its surface area.
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Answer 1

Answer:

Let the radius be r

Now the surface area = 4π(r) ² = 4πr²

The radius of the sphere is doubled.

The radius = 2r.

Now the surface area = 4π(2r)² = 16πr² .

Increase % in area = 16πr²-4πr²/4πr² * 100 = 12/4*100 = 300%

Answer 2

Answer:

300% IS INCREASED WHEN RADIUS IS DOUBLED.

Step-by-step explanation:

LET THE ORIGINAL RADIUS OF THE SPHERE BE r,

NOW THE SURFACE AREA OF THE SPHERE = 4π(r) ² = 4πr²

NOW THE RADIUS OF THE SPHERE IS DOUBLED,

THE DOUBLED RADIUS OF THE SPHERE = 2r.

DOUBLED RADIUS SURFACE AREA = 4π(2r)² = 16πr² .

INCREASE % IN AREA = 16πr²-4πr²/4πr² × 100 = 12/4 × 100 = 300% .

HOPE THE ANSWER IS CORRECT.