A car of mass 1400 kg moving south at 11 ms−1
collides into another car of mass 1800 kg
moving east at 30 ms−1
. The cars are stuck together after the collision. Determine the
velocity of the cars immediately after the collision.
Answers
Answered by
0
Given:
m1=1400kg
v1=11m/s
m2=1800kg
v2=30m/s
P1=√P1+P2=√(m₁²v₁²+m₂²v²₂)
=√(1400 ²x 11² + 1800² x30²)
≈56153kg.m/s
So, their final velocity when they struck together is
P=m X v
V=p/m=p/m1+m2
=56153/(1400+1800)
=17.55m/s
m1=1400kg
v1=11m/s
m2=1800kg
v2=30m/s
P1=√P1+P2=√(m₁²v₁²+m₂²v²₂)
=√(1400 ²x 11² + 1800² x30²)
≈56153kg.m/s
So, their final velocity when they struck together is
P=m X v
V=p/m=p/m1+m2
=56153/(1400+1800)
=17.55m/s
Answered by
1
Answer:
Mass1=1400kg V1=11m/s p1=m1v1 =1400×11 = 15400kg m/s M2=1800kg V2=30m/s p2= m2v2 =54000 kg m/s Total momentum before collision = p1 + p2 = 69400 kg m/s Total momentum before collision=total momentum after collision (by law of conservation of momentum) Momentum after collision = 69400 kg m/s Total mass = 3200kg (m1+m2) Let velocity of the cars after collision be x ATQ, 3200*x = 69400 (p=mv) x= 69400/3200 x=21.69 Hence velocity after collision - 21.69m/s
Similar questions