A car of mass 1500kg, increases its speed from 5 m/s to 25 m/s on a leveled road. Change in its potential energy is
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Answer: iven : Radius of the circular path r=20 m
Mass of the car M=1500kg
Speed v=12.5 m/s
Let the coefficient of friction be μ.
The centrifugal force will balance the friction force so that the car does not slip.
∴
r
mv
2
=μmg ⟹ μ=
rg
v
2
μ=
20×9.8
(12.5)
2
=0.8
Explanation:
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