Question

A car of mass 1800 kg moving with a speed of 10 m/s is brought to rest after a covering a of 50 m. Calculate the force acting on the car. ?

Answer 1

a= v^2/2s
v= 10
s= 50
a= 1
F = 1800 N

Answer 2

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Given That,

Mass of the car (m) = 1800 kg

Initial Velocity (u) = 10m/s

Final Velocity (v) = 0 m/s

Distance (s) = 50m

Then,

Force = ?

Therefore, We know that

$\bf {v}^{2} - {u}^{2} = 2 \times a \times s$

$\bf {0}^{2} + {10}^{2} = 2 \times a \times 50m$

$\bf 0 - 100 = a \times 100m$

$\bf a = \frac{ - 100}{100}$

$\bf a = - 1m/s$

Now,

Acceleration (a) = -1 m/s

Mass (m) = 1800 kg

Therefore,

Force = Mass × Acceleration

$\bf Force = 18000 \times - 1m/s$

$\bf Force = - 1800 N$

So,

The force acting on the car is -1800 N and the force acting on opposite of the direction of car is 1800 N.