Find the smallest number by which the following number should be multiplied to obtain a perfect cube i) 392 ii) 6125
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Prime Factorisation of 392=2*2*2*7*7
=14*14*2
Here 14 is in the pair but 2 is not in the pair .So, the smallest number by which 392 should be multiplied is 2
[392*2=784] and the ✓784=28
Prime Factorisation of 6125=5*5*5*7*7
=35*35*5
Here 35 is in the pair but 5 is not in the pair. So, the smallest number by which 6125 is multiplied is 5
[6125*5=30625] and the ✓30625=175
perfectly fine pure correct answer
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Prime Factorisation of 392=2*2*2*7*7
=14*14*2
Here 14 is in the pair but 2 is not in the pair .So, the smallest number by which 392 should be multiplied is 2
[392*2=784] and the ✓784=28
Prime Factorisation of 6125=5*5*5*7*7
=35*35*5
Here 35 is in the pair but 5 is not in the pair. So, the smallest number by which 6125 is multiplied is 5
[6125*5=30625] and the ✓30625=175
perfectly fine pure correct answer
hope it helps you mark me as brainliest and follow me
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