Question

A car of mass 2000 kg is moving with a speed of 10 ms–1 on a circular path of radius 20 m on a level road. The frictional force between the car and the road so that the car does not slip is
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Answer 1

Answer:

Given :         Radius of the circular path         r=20  m

                     Mass of the car        M=1500kg

                     Speed        v=12.5  m/s

Let the coefficient of friction be  μ.

The centrifugal force will balance the friction force so that the car does not slip.

∴     rmv2=μmg                         ⟹   μ=rgv2

μ=20×9.8(12.5)2=0.8