a car of mass 2000kg changes its speed from 72 km/h to 36km/h in 5 seconds what is the force applied by its brake
Answers
Explanation:
Given,
Mass of car, M=2000kg
Velocity, V=72×
18
5
=20ms
−1
Apply kinematic equation of motion
v
2
−u
2
=2as
0−20
2
=2a×20
a=−10ms
−2
Breaking force, F=ma=2000×10=20 kN
Apply first kinematic equation
v=u+at
t=
a
v−u
=
−10
0−20
=2 sec
Breaking force is 20 kNand time is 2sec.
4000 N is the force applied by its brake on a car of mass 2000kg changes its speed from 72 km/h to 36km/h in 5 seconds
Explanation:
Initial Speed = 72 km/hr = 72 * 5 /18 = 20 m/s
Final Speed = 36 km/hr = 36 * 5/18 = 10 m/s
acceleration = Change in Velocity / time
=> acceleration = ( 10 - 20)/5
=> acceleration = -10/5
=> acceleration = -2 m/s²
Hence there is a deceleration of 2 m/s² due to force applied by break
force applied by its brake = mass * acceleration
=> 2000 * 2
= 4000 N
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