A car of mass 2400 kg moving with a velocity of 20 m per second is stopped in 10 second on applying brake calculate the retardation and the retarding of force
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Answered by
8
Negative acceleration on the car,
v = u+at
a = (v-u)/t
a = (0-20)/10
a = -2 m/s²
Now force,
F = ma
F = 2400×(-2)
F= -4800N
v = u+at
a = (v-u)/t
a = (0-20)/10
a = -2 m/s²
Now force,
F = ma
F = 2400×(-2)
F= -4800N
Answered by
1
given,
m=2400 kg
v =20m/s
t = 10s
retardation =?
retarding =?
retardation =v/t
= 20/ 10
= 2 m/s²
retarding = m x retardation
=2400 x 2
=4800
m=2400 kg
v =20m/s
t = 10s
retardation =?
retarding =?
retardation =v/t
= 20/ 10
= 2 m/s²
retarding = m x retardation
=2400 x 2
=4800
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