Question

A car of mass 2500 KG travelling at a speed of 40 m/s stops after covering a distance. of 50m calculate the force exerted by the brakes and also the work done by the brakes

Answer 1

F=ma
m=2500kg
a=?
but wkt
u=40mps
v=0
so=50

by 3rd equation of motion
v^2=u^2+2aS
so,
o=1600-x(100)
x=1600/100
x=a=-16mps^2

if
F=ma
F=2500(-16)
F= -40,000 Newton
(-ve) sing denetos that force is applied in the opposite direction of motion.

Answer 2

Answer:

F=ma

m=2500kg

a=?

but wkt

u=40mps

v=0

so=50

by 3rd equation of motion

v^2=u^2+2aS

so,

o=1600-x(100)

x=1600/100

x=a=-16mps^2

if

F=ma

F=2500(-16)

F= -40,000 Newton

(-ve) sing denotes that force is applied in the opposite direction of motion.