Question

a car of mass 3000 kg travelling at a speed of 108 km per hour collides with a building and is stopped in 0.8 second. what is the impulse exerted on the car?​

Answer 1

Answer:

90000 kg m/s

Explanation:

Initial momentum of car = mu

= 3000 kg × 108 kmph

= 3000 kg × 108 × 5/18 m/s

= 90000 kg m/s

Final momentum of car = mv

= 3000 kg × 0 m/s

= 0 kg m/s

Impulse = Change in momentum

= Final momentum - Initial momentum

= 0 kg m/s - 90000 kg m/s

= 90000 kg m/s

Answer 2

Answer:

9000 km per h is the answer

ok