a car of mass 3140 kilogram is supported on hydraulic lift with a circular piston of diameter 1.0m. calculate the Pressure transmitted .take g=10m s-2 and pie=3.14
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hey buddy hope it help
given : mass= 3140 kg
diameter = 1.0
radius = 1/2 = 0.5
g= 10 m/s^2
pie = 3.14.
pressure = h* rho* g ( where rho is density = mass / volume)
p= h* m/V* g
p= h* m/A*h*g ( where A is area )
p= 3140/3.14*(0.5)^2*10
p = 4000 *10 = 40000 N/m^2=40kN/m^2
hope it help u
given : mass= 3140 kg
diameter = 1.0
radius = 1/2 = 0.5
g= 10 m/s^2
pie = 3.14.
pressure = h* rho* g ( where rho is density = mass / volume)
p= h* m/V* g
p= h* m/A*h*g ( where A is area )
p= 3140/3.14*(0.5)^2*10
p = 4000 *10 = 40000 N/m^2=40kN/m^2
hope it help u
prabhjit:
today morning is my paper and my practicing numericals
ok hope it help u
if yu found any mistake please tell me
ok brother
brother from where 4000 came???
brother by solving 3140/ 3.14*(0.5)^2
ok i came to know thanks
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