Question

The perimeter of rectangle is 70 cm if its length exceed its breadth by 5 cm, find dimension

Answer 1

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Answer 2

${\huge{\boxed{\sf{\green{❥✰Question✰}}}}}$

The perimeter of rectangle is 70 cm if its length exceed its breadth by 5 cm, find dimension.

${\huge{\underline{\bf{\pink{❥✰➵ANSWER :-✰}}}}}$

The perimeter of a rectangle is 70 cm.

Its length exceeds its breadth is 5 cm.

To Find :-

What is the area of the rectangle.

Formula Used :-

$\clubsuit♣$ Perimeter of Rectangle :

$\begin{gathered}\longmapsto \sf\boxed{\bold{\pink{Perimeter\: Of\: Rectangle =\: 2(Length + Breadth)}}}\\\end{gathered}$

⟼

Perimeter Of Rectangle=2(Length+Breadth)

$\clubsuit♣$ Area of Rectangle :

$\begin{gathered}\longmapsto \sf\boxed{\bold{\pink{Area\: Of\: Rectangle =\: Length \times Breadth}}}\\\end{gathered}$

Solution :-

Breadth of a rectangle be x cm

Length of a rectangle will be x + 5 cm

Given :

Perimeter = 70 cm

According to the question by using the formula we get

$\implies \sf 2(x + x + 5) =\: 70⟹2(x+x+5)=70\implies \sf 2(2x + 5) =\: 70⟹2(2x+5)=70\implies \sf 2x + 5 =\: \dfrac{\cancel{70}}{\cancel{2}}⟹2x+5= 2​ 70$

$\implies \sf 2x + 5 =\: 35⟹2x+5=35\implies \sf 2x =\: 35 - 5⟹2x=35−5\implies \sf 2x =\: 30⟹2x=30\implies \sf x =\: \dfrac{\cancel{30}}{\cancel{2}}⟹x= 2​ 30$

$implies \sf\bold{\green{x =\: 15\: cm}}⟹x=15cm$

Hence, the required length and breadth are :

Breadth of Rectangle :

$\implies \sf x\: cm⟹xcm\implies \sf\bold{\red{15\: cm}}⟹15cm$

And,

$\dashrightarrow⇢ Length of Rectangle :\implies \sf x + 5\: cm⟹x+5cm\implies \sf 15 + 5\: cm⟹15+5cm\implies \sf\bold{\purple{20\: cm}}⟹20cm$

Now, we have to find the area of the rectangle :

Given :

Length = 20 cm

Breadth = 15 cm

According to the question by using the formula we get,

$\leadsto \sf Area\: of\: Rectangle =\: 20\: cm \times 15\: cm⇝AreaofRectangle=20cm×15cm$

$\leadsto \sf\bold{\red{Area\: of\: Rectangle =\: 300\: cm^2}}⇝$

The area of the rectangle is 300 cm².