The present age of a father is 3 years more than three times the age of his son. three years hence, father's age will be 10 years more than twice the age of the son. find the present age of the father. (a) 32 years (b) 33 years (c) 34 years (d) 35 years (e) 40 years
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let the present age of son be x yrs and his father's age be (3x+3)yrs
3 yrs after,
son's age=(x+3)yrs
father's age=(3x+3+3)yrs
=(3x+6) yrs
A/Q
3x+6=2(x+3)+10
3x+6=2x+6+10
3x-2x=16-6
x = 10
Hence,
father's present age=(3×10+3) yrs
=33 yrs
(b) 33 yrs is the correct answer
hopes it helps you....
3 yrs after,
son's age=(x+3)yrs
father's age=(3x+3+3)yrs
=(3x+6) yrs
A/Q
3x+6=2(x+3)+10
3x+6=2x+6+10
3x-2x=16-6
x = 10
Hence,
father's present age=(3×10+3) yrs
=33 yrs
(b) 33 yrs is the correct answer
hopes it helps you....
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