Question

A car of mass 400 Kg pulling a coach of mass 300 kg with a force of 4500 Newton. if the coefficient of friction is 0.001 what is tension?

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Answer 1

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Answer 2

Answer:

The tension in the wire is 1928,6 N.

Explanation:

Given,

Mass of car (m1) = 400 Kg

Mass of the coach (m2) = 300 Kg

Applied force(F) = 4500

Coefficient of friction (μ) = 0.001

To find,

The tension in the wire(T).

Calculation,

First, we find the acceleration with which the system is moving:

i.e. F - μ(m1 + m2)g = (m1 + m2) × a

⇒ 4500 - 0.001(700)(10) = 700a

⇒ 4500 - 7 = 700a

⇒ 4493 = 700a

⇒ a = 4493/700 m/s²

Now we find the tension developed in the wire connected between the car and the coach.

i.e. T - μ(m2)g = m2 × a

⇒ T = m2 × a + μ(m2)g

⇒ T = 300 (4493/700) + 0.001(300)(10)

⇒ T = 1928.6 N

Therefore, the tension in the wire is 1928,6 N.

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