Question

A CAR OF MASS 800 KG IS TRAVELLING WITH VELOCITY 20 M/S. WHEN BRAKES ARE APPLID IT STOP AFTER TRAVELLING 8 M . FIND RETADDATION AND FORCE. 3 MARKS

Answer 1

Explanation:

Answer:

Given:

mass(m)=800kg

initial velocity (u)=20 m/s

final velocity (v) =0 m/s

distance(s)= 8m

We have to find acceleration which is the retardation.

2as = v square - u square

2a×8 = 0 square × 20 square

16a= - 400

a=-400/16

a= -25 m/s

Retarding force:

F=ma

F= 800 × (-25)

F= -20000N

Answer 2

Explanation:

Answer:

Given:

mass(m)=800kg

initial velocity (u)=20 m/s

final velocity (v) =0 m/s

distance(s)= 8m

We have to find acceleration which is the retardation.

2as = v square - u square

2a×8 = 0 square × 20 square

16a= - 400

a=-400/16

a= -25 m/s

Retarding force:

F=ma

F= 800 × (-25)

F= -20000N