Question

a car of mass 800 kg moves on a circular track of radius 40 m if the coefficient friction is 0.5 then the maximum velocity with which the car can movies​

Answer 1

Answer:

The answer is 14.14 m/s

Explanation:

For circular tract maximum velocity is equal to (coefficient of friction*radius*g)^1/2

V(max) = √  μ x r x g

Given data:

 μ = 0.5

r = 40 m

g = 10

Now put the values in above formula

V(max) = √  0.5 x 40 x 10

V(max) =  √ 200

V(max) = 14.14 m/s