a car of mass 800 kg travelling at a speed of 10 ms is brought to rest in 20 seconds by applying brakes.Calculate the average braking force acting on the wheels.
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Here, initial velocity is 10ms and final is 0 as brakes are applied and time taken is 20 sec
So, acceleration =final velocity - initial velocity
By Time taken
Acceleration =0-10/20
Acceleration= -1/2 m/s square
Now,
Force = mass×acceleration
Force=800kg × - 1/2
Force= - 400 newtons
This means that when brakes are applied 400 newton friction is applied on the wheels as negative sign is given.
This was your answer. Please mark me as brainliest.
So, acceleration =final velocity - initial velocity
By Time taken
Acceleration =0-10/20
Acceleration= -1/2 m/s square
Now,
Force = mass×acceleration
Force=800kg × - 1/2
Force= - 400 newtons
This means that when brakes are applied 400 newton friction is applied on the wheels as negative sign is given.
This was your answer. Please mark me as brainliest.
Answered by
0
Answer:
ajemksri
Explanation:
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