Physics, asked by aryanjhinkwan007, 7 months ago

A car of mass 800kg is travelling around a circular path of radius 200m with a speed of 10ms⁻¹. Its angular momentum is *

(a) 1.6 x 104 kgm²s⁻¹

(b) 1.6 x 106 kgm²s⁻¹

(c) 1.6 x 108 kgm²s⁻¹

(d) 1.6 x 1010 kgm²s⁻¹

Answers

Answered by EliteSoul
28

Correct question

A car of mass 800kg is travelling around a circular path of radius 200m with a speed of 10ms⁻¹. Its angular momentum is :

(a) 1.6 x 10⁴ kgm²s⁻¹

(b) 1.6 x 10⁶ kgm²s⁻¹

(c) 1.6 x 10⁸ kgm²s⁻¹

(d) 1.6 x 10¹⁰ kgm²s⁻¹

Given

  • Mass of car = 800 kg
  • Radius of path = 200 m
  • Speed of car = 10 ms⁻¹

To find

  • AnguIar momentum of car

Soiution

From question we have :

⇔ Mass of car (m) = 800 kg

⇔ Radius of path (r) = 200 m

⇔ Speed of car (v) = 10 ms⁻¹

Now we know the formuIa :

⇔ AnguIar momentum (L) = p * r = m * v * r

Substituting vaIues :

⇒ L = 800 * 10 * 200

⇒ L = 8000 * 200

⇒ L = 1,600,000 kgm²s⁻¹

L = 1.6 × 10⁶ kgm²s⁻¹  [ Option (b) ] --- Answer

AdditionaI informations

⊕ AnguIar momentum is the rotationaI equivaIent of Iinear momentum.

⊕ SI units : kgm²s⁻¹

⊕ Derivation : L = lω = p * r = m * v * r

⊕ Dimension = ML²T⁻¹


Anonymous: Great :)
EliteSoul: Thanks!
Answered by sudershanswain120995
2

Answer:

ar of mass 800kg is travelling around a circular path of radius 200m with ... Its angular momentum is * (a) 1.6 x 104 kgm²s⁻¹ (b) 1.6 x 106 kgm²s⁻¹ (c) 1.6 x 108 kgm²s⁻¹ ... Plzz Download Quanda application scan and Solve your Question ... The time rate of change of momentum gives the measure of *(a) ...

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