Question

. A car of mass one metric ton accelerates from
rest at the rate of 2 m/s2 from t = 0 sec to
t = 10 sec. There after it travels with a uniform
velocity. The measure of net retarding force
acting on the car after 10 sec is​

Answer 1

Answer:

0 N

Explanation:

Given,

Mass of a car(m)  = 1 metric ton

= 1000 kg

Initial Velocity(u) = 0 m/s

Acceleration(a) = 2m/s^2 from t = 0 sec to t = 10sec

After 10sec car  travels with a uniform velocity.

To Find :-

Net retarding force acting on the car after 10 sec.

Solution :-

According to question :-

After 10sec car  travels with a uniform velocity.

→ Acceleration of the car will be '0' m/s^2

$\bf Force=mass\times acceleration$

$\implies F=m\times a$

F = m × 0

= 0

→ F = 0N

∴ Net retarding force  acting on the car after 10 sec is​ '0N' because the car stops accelerating after 10 sec.

Know More :-

1) F = ma

• F = Force
• m = mass
• a = acceleration

2) a = v - u/t

• a = acceleration
• v = final velocity
• u = initial velocity
• t = time

3) v = u + at

• a = acceleration

• v = final velocity
• u = initial velocity
• t = time

Answer 2

Given,

Mass of a car(m) = 1 metric ton

= 1000 kg

Initial Velocity(u) = 0 m/s

Acceleration(a) = 2m/s^2 from t = 0 sec to t = 10sec

After 10sec car travels with a uniform velocity.

To Find :-

Net retarding force acting on the car after 10 sec.

Solution :-

According to question :-

After 10sec car travels with a uniform velocity.

→ Acceleration of the car will be '0' m/s^2

Force=mass×acceleration

a⟹F=m×a

F = m × 0

= 0

→ F = 0N

∴ Net retarding force acting on the car after 10 sec is '0N' because the car stops accelerating after 10 sec.

Know More :-

1) F = ma

F = Force

m = mass

a = acceleration

2) a = v - u/t

a = acceleration

v = final velocity

u = initial velocity

t = time

3) v = u + at

a = acceleration

v = final velocity

u = initial velocity

t = time